How To Find Square Numbers From Given List Using Python?

How to findout Square Number.

Introduction

As we all knew about square number. In mathematics square number or perfect square number is a number which is product of number with itself. For example 4 * 4 = 16, 2 * 2 = 4, 6 * 6 = 36.

My goal here is to try to write basic Python code to solve the grade 4 problem.

How to do it ?

My basic concept is here I gave numbers in the specified numbers of range and initialize empty list to store the result. And applied appropirate condition.

In Python

My basic concept is here I gave numbers in the range 1 to 101 to find the square numbers between 1 to 100. We already had known that in a range lower point is inclusive and the upper point is exclusive. so, here I took range 1 to 101. I made an empty list to store the square numbers. And I applied for a loop. And I define root which is given iteration variable’s power one upon two. I round the int_root. Usage​​ of round() function is which returns a floating-point number that is a rounded version of the specified number, with the specified number of decimals. And I applied the condition if int_root’s power 2 is equal to n then that an iteration variable is a perfect number and it goes to the root_numbers list. A similar process is applied for all of the iteration variables until the last iteration variable is 100.

numbers = list(range(1,101))
root_numbers = []
for n in numbers:
    root = (n)**0.5
    int_root = round(root)
    if int_root**2 == n:
        root_numbers.append(n)
        print(n)

Output of the above code is

1
4
9
16
25
36
49
64
81
100